Math, asked by vikky98, 1 year ago

if a and b are positive integers then a+b+ab=65 , find (a-b) . [a,b<=15]. ......don't use number substitution solve it

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Answered by sunanakumari

Answer:

Step-by-step explanation:

65=13X5 --> only combination

a+b+ab=65

b(a/b+1+a)=13X5

if b=5-->

5(a/5+a+1)=65

a/5 +1+a= 13

6a+5=65

6a=60

a=10, b=5

a-b=5

vikky98: how you are taking b > 5

vikky98: how b is less than 5

sunanakumari: dividing lhs and rhs by 5

sunanakumari: since 65 s divisible by 5

sunanakumari: lhs is assumed to be dvisible by 5

vikky98: ok

sunanakumari: pls mark as brainliest

sunanakumari: you can also do the procedure i have told above by dividing both sides by 13 and assuming b=13,but we see at end that a becomes 52/14 which is not an integer .But as per question a and b are integers .so only way is b=5 where we get a as integer

vikky98: ok

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if a and b are positive integers then a+b+ab=65 , find (a-b) . [a,b<=15]. ......don't use number substitution solve it​

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if a and b are positive integers then a+b+ab=65 , find (a-b) . [a,b<=15]. ......don't use number substitution solve it