If a and b are positive integers with no common factor
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a and b are integer but It may be negative
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If x,y∉Z and x+y∈Z, then ⌊x⌋+⌊y⌋=x+y−1. Therefore,
⌊jab⌋+⌊(b−j)ab⌋=a−1(1)
If (a,b)=1, then for 0<j<b, we have jab∉Z.
Summing (1), we get
∑j=1b−1⌊jab⌋+⌊(b−j)ab⌋=(a−1)(b−1)(2)
(2) counts each term in the sum we want twice, so we get
∑j=1b−1⌊jab⌋=(a−1)(b−1)2(3)
Hope this helps ☺️☺️☺️
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