Question

if a and b are rational number and 6/3√2-2√3 = a√2-b√3, then find the value of a and b

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

Given ;

6 / 3√2 - 2√3 = a√ 2 - 2√3

Rationalisation ;

6/ 3√2 - 2√3 × 3√2 + 2√3 / 3√2 + 2√3

= 6( 3√2 + 2√3 ) / (3√2)² - (2√3)²

= 18 √2 + 12 √3 / 18 - 12

= 6 ( 3√2 + 2√3 ) / 6 ( 3 - 2 )

( 6 and 6 get cancelled)

= 3√2 + 2√3 / 1 = 3√2 + 2√3

Hence , a√2 = 3√2

b √ 3 = 2√3 .

So , we can say that a = 3, b = 2 . ( ans )..

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