Question

if A and B are rational number and 6/3√2-2√3=a√2-b√3 then find the value of of a and b ​

Answer 1

∆ Given :

${\small{\sf{• \ \ \ \dfrac{6}{3\sqrt{2}} - 2\sqrt{3} = a\sqrt{2} - b\sqrt{3}}}}$

∆ To Find :

• Find the value of a & b ?

∆ Solution :

Solving LHS

${\small{\tt{\implies{\dfrac{\cancel{6}}{\cancel{3}\sqrt{2}} - 2\sqrt{3}}}}}$

${\small{\tt{\implies{\dfrac{2}{\sqrt{2}} × \dfrac{\sqrt{2}}{\sqrt{2}} - 2\sqrt{3}}}}}$

${\small{\tt{\implies{\dfrac{\cancel{2}\sqrt{2}}{\cancel{2}} - 2\sqrt{3}}}}}$

${\small{\tt{\implies{\sqrt{2} - 2\sqrt{3}}}}}$

On comparing , We get

${\small{\tt{\longmapsto{\sqrt{2} - 2\sqrt{3} = a \sqrt{2} - b\sqrt{3}}}}}$

${\huge{\fcolorbox{black}{skyblue}{ \boxed{\frak{ \red{a= 1 \ \ \ and\ \ b = 2}}}}}}$

Answer 2

Answer:

change language OK bye bye