Question

❤️❤️❤️❤️❤️✌️if a and b are rational numbers and 7-4√3/7+4√3=a+b√3...find a and b plz answer its urgent....who will answer me i will thank their answers​

Answer 1

$\huge{\mathfrak{\pink{Answer}}}$

$\frac{7 - 4 \sqrt{3} }{7 + 4 \sqrt{3} } = a + b \sqrt{3} \\ \\ \frac{7 - \sqrt{3} }{7 + \sqrt{3} } \times \frac{7 - \sqrt{3} }{7 - \sqrt{3} } = a + b \sqrt{3} \\ \\ \frac{(7 - \sqrt{3} ) (7 - \sqrt{3} }{(7) {}^{2} - ( \sqrt{3} ) {}^{2} } = a + b \sqrt{3} \\ \\ \frac{49 - 7 \sqrt{ 3} - 7 \sqrt{3} + 3 }{49 - 3} = a + b \sqrt{3} \\ \\ \frac{52 - 14 \sqrt{3} }{46} = a + b \sqrt{3} \\ \frac{52}{46} + ( \frac{ - 14 \sqrt{3} }{46} ) = a + b \sqrt{3} \\ \\ a = \frac{52}{46} \\ \\ b = \frac{ - 14}{46}$

Answer 2

Step-by-step explanation:

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