if a and b are rational numbers and root 3+root 2/root 3 -root 2=a+b root6.then find the values of a and b
ayush31102003:
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i think a=5 and b=2
ya u r right
thanks
i gust kept high points thus u guyz solved
anyway thanks
amrendra bas kar
i just like helping no prob even if less points
sorry amrendra sir bas karo
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Given:
(√3+√2)/(√3-√2) =a+b√6
Multiplying numerator and denominator of LHS with (√3+√2) we get―
=(√3+√2)(√3+√2)/[(√3-√2)(√3+√2)]
=[(√3+√2)^2]/(3-2) [using (a+b)(a-b)=a^2-b^2]
=(3+2+2√6)/1
=5+√6
On comparision with a+b√6, we see–
a=5 and b=2
[Answer]
(√3+√2)/(√3-√2) =a+b√6
Multiplying numerator and denominator of LHS with (√3+√2) we get―
=(√3+√2)(√3+√2)/[(√3-√2)(√3+√2)]
=[(√3+√2)^2]/(3-2) [using (a+b)(a-b)=a^2-b^2]
=(3+2+2√6)/1
=5+√6
On comparision with a+b√6, we see–
a=5 and b=2
[Answer]
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