Question

if a and b are rational numbers then find the value of a and b
√3- 1÷√3 + 1 = a+b√3

Answer 1

$\frac{ \sqrt{3 } - 1}{ \sqrt{3 } + 1} \times \frac{ \sqrt{3 } - 1}{ \sqrt{3 } - 1 }$
$\frac{ { (\sqrt{3} - 1) }^{2} }{ { \sqrt{3} }^{2} - {1}^{2} } = \frac{3 + 1 - 2 \sqrt{3} }{3 - 1}$
$\frac{4 - 2 \sqrt{3} }{2} = \frac{2(2 - \sqrt{3 }) }{2}$
$= 2 - \sqrt{3}$
comparing with a+b/3
a=2 b=-1

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Answer 2

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