If a and b are real and ( i+3i)a +(i-1)b+5i^3=0 find a and b
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Solve it by converting it to a system of linear equations.
By expanding the terms, you get 2a−3ai+3b−2bi=0+5i.a−3ai+3b−2bi=0+5i.
Now grouping the real parts and imaginary parts together gives,
2a+3b=02a+3b=0 and −3a−2b=5.−3a−2b=5.
Now solve this system whichever way you prefer(Example: Matrix equation, simultaneous equation). I’ll proceed by multiplying the first equation by 33 and the second equation by 22and then adding them up together.
6a+9b−6a−4b=106a+9b−6a−4b=10
So b=2.
PLZ mark me as a BRAINLIST
By expanding the terms, you get 2a−3ai+3b−2bi=0+5i.a−3ai+3b−2bi=0+5i.
Now grouping the real parts and imaginary parts together gives,
2a+3b=02a+3b=0 and −3a−2b=5.−3a−2b=5.
Now solve this system whichever way you prefer(Example: Matrix equation, simultaneous equation). I’ll proceed by multiplying the first equation by 33 and the second equation by 22and then adding them up together.
6a+9b−6a−4b=106a+9b−6a−4b=10
So b=2.
PLZ mark me as a BRAINLIST
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