if A and B are real number and a^2 + b^2 + 8a - 14b + 65 = 0 , find a and b
Answers
Answered by
15
Given,
It is given that a and b are real numbers and a² + b² + 8a -14b + 65 =0.
To find,
We have to find the values of a and b.
Solution,
The value of a and b are -4 and 7 ,respectively.
It is given that a² + b² + 8a -14b + 65 =0, we can write 65 as the sum of 16 and 49.
a² + b² + 8a -14b + 16 +49 =0
a² + 8a +16 +b²-14b+49 =0
(a+4)² + (b-7)² = 0
(a+4)² = 0
a = -4
(b-7)² = 0
b = 7
Hence, the value of a is -4 and b is 7.
Answered by
1
Answer:
Answer is a = -3 and b=7. Therefore, a+b = 3
Step-by-step explanation:
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