Question

if a and b are roots of 3x2-6x+2=0 then find a+b & ab & 1/a+1/b

Answer 1

a+b=2
ab=2/3
1/a+1/b=3

Answer 2

If a and b are the roots of $3x^2-6x+2=0$ then $a+b = 2 , a.b=1/3 , 1/a+1/b=6.$

Given:

a and b are the roots of $3x^2-6x+2=0$

To find :

The value of $a+b,ab$ and $1/a+1/b$.

Solution :

Given that $3x^2-6x+2=0$

Here, a=3,b=−6,c=1

Then,

$a+b=-b/a$

$a+b =-(-6)/3\\a+b=2$

Therefore,

$a.b=c/a\\\\a.b=1/3$

Therefore,

$1/a+1/b=a+b/ab\\\\1/a+1/b=2/(1/3)\\\\1/a+1/b=6$

Thus,$a+b = 2 , a.b=1/3 , 1/a+1/b=6$,

#SPJ3