If a and b are roots of polynomial x^2-2x-15 then form a quadratic polynomial whose zeros are 2a+1 and 2b-1
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x^2 -2x-15=2a+1+2b-1
2a-2x-2b=x^2-15
-6abx = x^2 -15
abx^2 = x^2 -15+6
abx ^2=x^2 -3^3
side of the no. of power
2=2-3
2-3-2
3
2a-2x-2b=x^2-15
-6abx = x^2 -15
abx^2 = x^2 -15+6
abx ^2=x^2 -3^3
side of the no. of power
2=2-3
2-3-2
3
Answered by
1
roots for given question are -3 and 5
let a= -3 ans b= 5
let the polynomial whose roots are 2a+1 and 2b-1 is x^2-((2a+1)+(2b-1))+(2a+1)(2b-1)=0
now substitute the values of a and b respectively.
hence the polynomial will be x^2-4x-45
let a= -3 ans b= 5
let the polynomial whose roots are 2a+1 and 2b-1 is x^2-((2a+1)+(2b-1))+(2a+1)(2b-1)=0
now substitute the values of a and b respectively.
hence the polynomial will be x^2-4x-45
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