If a and b are roots of the equation 2x^2-10x+5=0.find the value of ( a +2)(b +2)
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root of first eq a = 1 and b = 5/2
so new root = a+2 =a'= 3 and b+2 =b' = 9/2 so new equation =
wait I think something wrong with question
so new root = a+2 =a'= 3 and b+2 =b' = 9/2 so new equation =
wait I think something wrong with question
Answered by
3
A=2,. B=-10 C= 5
a+b=-b/a=-(-10)/2 =5
ab= c/a= 5/2
(a+2)(b+2)=ab+2(a+b)+4
5/2+2(5)+4=5/2+14=33/2
This will help u
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