If a and b are roots of the equation x² + ax + b = 0, then a + b =
(a)1
(b)2
(c)−2
(d)−1
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SOLUTION :
Option (d) is correct : - 1
Given : ‘a’ & 'b’ are the roots of the equation x² + ax + b = 0
On comparing the given equation with ax² + bx + c = 0
Here, a = 1 , b = a , c = b
Sum of zeroes = - b/a
a + b = - b/a
a + b = - a/1
a + b = - a
b = - a - a
b = - 2a ………..(1)
Product of zeroes = c/a
a × b = c/a
ab = b/1
ab = b
a = b/b
a = 1
On putting the value of a = 1 in eq 1
b = - 2a
b = - 2(1)
b = - 2
The value of a + b = 1 + (- 2)
a + b = 1 - 2
a + b = - 1
Hence, the value of (a + b) is - 1.
HOPE THIS ANSWER WILL HELP YOU...
Anonymous:
Nice, but you can save time (the extra steps to find b are redundant). Once you got a+b=-a and a=1, you have the answer... a + b = -a = -1.
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the a+b = 1 ok frnd isse aage nahi kr sakte
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