if A and b are roots of x^2-bx+c=0 then ab^3+a^3b=
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Sum of roots is
a+b=-(-b/1)=b
.
Product of root is
Ab=c/1=c
A=c/b and b=c/a
.
hence ab^3+a^3b=c/b²+c/a²
=>c(1/a²+1/b²)
=>c(a²+b²)/a²b²
=>c(a²+b²)/c=>a²+b²
=>(a+b)²-2ab
=>b²-2c
.
hope this helps you.
keep smiling
.
mark this as brainliest answer
a+b=-(-b/1)=b
.
Product of root is
Ab=c/1=c
A=c/b and b=c/a
.
hence ab^3+a^3b=c/b²+c/a²
=>c(1/a²+1/b²)
=>c(a²+b²)/a²b²
=>c(a²+b²)/c=>a²+b²
=>(a+b)²-2ab
=>b²-2c
.
hope this helps you.
keep smiling
.
mark this as brainliest answer
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