Question

If a and B are roots of x2 + 7x + 12 = 0, then the
equation whose roots are (a + b)2 and (a - b) is
(a) x2 – 50x + 49 = 0 D)
(b) x2 + 50x – 49 = 0
(C) x2 – 10x + 3 = 0
(d) x2 – 10x + 4 = 0 wollt in W
(C) x2 - 10x + 9 = 0
litsus​

Answer 1

Answer:

Step-by-step explanation:

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Answer 2

Answer:

a+b=-7

2(a+b)=-14

now ..ab =12

therefore...

(a-b)^2=(a+b)^2-4ab=49-48=1

(a-b)=1

therefore ....a=-3.....b=-4

now,(a+b)^2=49=p(let)

(a-b)=1=q(let)

pq=49.....p+q=50

therefore the equation is

x^2-50x+49=0

now ....