If A and B are the angles of a right angled triangle ABC, right angled
at C then 1+cot2A =
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ABC is right angle ∆
so,
A + B + 90° = 180°
A + B = 90°
A = 90 -B
multiply with 2
2A = 180 -2B
take cot both sides
cot2A = cot(180-2B ) = - cot2B
add 1 both sides
1 + cot2A = 1- cot2B
hence,
(1 + cot2A) = (1 -cot2B)
so,
A + B + 90° = 180°
A + B = 90°
A = 90 -B
multiply with 2
2A = 180 -2B
take cot both sides
cot2A = cot(180-2B ) = - cot2B
add 1 both sides
1 + cot2A = 1- cot2B
hence,
(1 + cot2A) = (1 -cot2B)
Anonymous:
tq dear abhi
:-)
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