if A and B are the non zero distinct roots of x^2
+ a x + b = zero then the least value of x^2 + aX + b is what
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The least value of x^2 + aX + b is - 9/4.
Step-by-step explanation:
x^2 + ax + b > a - b
First fond the values of a and b.
a + b = - a ab = b
b + 2a = 0 ------(1) ab - b = 0
B + 2 = 0 b ( a - 1 ) = 0
b = -2 b = 0 ; a = 1
x^2 + ax + b
x^2 + x - 2
x^2 + x + (1/2)^2 - (1/2)^2 - 2
( x +1/x )^2 - 1/4 - 2
(x + 1/2 )^2 - 9 / 4
Hence the least value of x^2 + aX + b is - 9/4.
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Answer:least value of x²+ax+b is -9/4
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