Math, asked by qwerty89, 1 year ago

if A and B are the non zero distinct roots of x^2
+ a x + b = zero then the least value of x^2 + aX + b is what

Answers

Answered by Fatimakincsem
11

The least value of x^2 + aX + b is - 9/4.

Step-by-step explanation:

x^2 + ax + b > a - b

First fond the values of a and b.

a + b = - a                                            ab = b

b + 2a = 0 ------(1)                                ab - b = 0

B + 2 = 0                                             b ( a - 1 ) = 0

b = -2                                                   b = 0 ; a = 1

x^2 + ax + b

x^2 + x - 2

x^2 + x + (1/2)^2 - (1/2)^2 - 2

( x +1/x )^2 - 1/4 - 2

(x + 1/2 )^2 - 9 / 4

Hence the least value of x^2 + aX + b is - 9/4.

Answered by nikhilsrinivas22
6

Answer:least value of x²+ax+b is -9/4

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