If a and b are the rational numbers and 4+3√5/4-3√5 = a+ b√5, then find a and b????
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Step-by-step explanation:
4+3√5/4-3√5×4+3√5/4+3√5=
(4+3√5)(4+3√5)/(4-3√5)(4+3√5)=
(4+3√5)^2/4^2-(3√5)^2=
4^2+2×4×3√5+(3√5)^2/4^2-(3√5)^2=
16+24√5+45/16-45=
61+24√5/-29=a+b√5
a=-61/29;b=-24/29
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