if A and B are the root of equation X square + a x minus b
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Given equation x^2 +ax +b=0,
Sum of roots = a+b = -a,
2a+b=0.
Product of roots= ab = b,
For non-zero format, a=1, b = -2.
Hence function is f(x) = x^2 +x -2.
so x =-1/2.
Putting this value in above f(x),
f(-1/2) = 1/4 -1/2 -2 = -9/4.
So minimum value will be -9/4.
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if A and B are the root of equation X square + a x minus b
A & B are the roots of X² + ax - b
As A & B are roots of polynomial
So equation is
(X - A)(X-B)
= X² - AX - BX + AB
=> X² -(A+B)X + AB
Equating with
X² + ax - b
A+B = -a
AB = - b
if We assume A & a are same thing & also B & b is same
then
ab = -b
=> a = -1
a + b = -a
=> -1 + b = 1
=> b = 2
Then X² + ax - b = X² -X -2
X² -X -2
= X² - 2X + X - 2
= X(X-2) +1(X-2)
= (X+1)(X-2)
A = - 1 & B = 2
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