If a and b are the roots of 6x^2-7x-3, find the value of a^2+b^2
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HEY,,
HERE IS YOUR SOLUTION...,,
6x^2 - 7x - 3 = 0
6x^2 - 9x + 2x - 3 = 0
3x(2x - 3) +1(2x - 3) = 0
(3x+1) (2x-3) = 0
(3x+1) = 0 or (2x - 3) = 0
x = -1/3 or x = 3/2
-–-----------////--------------////----------–--////-----–------
let,,
a = -1/3 and b = 3/2
= a^2 + b^2
= (-1/3)^2 + (3/2)^2
= 1/9 + 9/4
= 4 + 81/36
= 85/36
= 2.36
... HOPE IT HELPS YOU...
... THANKS ......
HERE IS YOUR SOLUTION...,,
6x^2 - 7x - 3 = 0
6x^2 - 9x + 2x - 3 = 0
3x(2x - 3) +1(2x - 3) = 0
(3x+1) (2x-3) = 0
(3x+1) = 0 or (2x - 3) = 0
x = -1/3 or x = 3/2
-–-----------////--------------////----------–--////-----–------
let,,
a = -1/3 and b = 3/2
= a^2 + b^2
= (-1/3)^2 + (3/2)^2
= 1/9 + 9/4
= 4 + 81/36
= 85/36
= 2.36
... HOPE IT HELPS YOU...
... THANKS ......
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