If a and b are the roots of ax2+bx+c=0 then (1/a2)+(1/b2) is Plzz give the answer Question no 4
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The given question is solved in the uploaded photo
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Answer:
(b²- 2ac)/ac
Step-by-step explanation:
α+β = -b/a
αβ= c/a
1/α²+1/β²=(α²+β²) ÷ (αβ)²=((α+β)²-2αβ) ÷ (αβ)²=(b²/a² - 2c/a) ÷ (c/a) ²
=((b²- 2ac)/a²) ÷ (c²/a²)
=(b²- 2ac)/c²
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