if a and b are the roots of equation X2+3x+2=0 find the value of A2+b2
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Step-by-step explanation:
p(x)=x²+3x+2=0
S=3
P=2
→x²+2x+x+2=0
x(x+2)+1(x+2)=0
x+1=0
x=-1(alpha-root1)
x+2=0
x=-2(beta-root2)
A²+B²=(a+b)²-2ab
→((-1)+(-2))²-2×(-1×-2)
→-3-4=-7
A²+B²=-7
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