Question

If a and B are the roots of px^2 - qx + c then a + ß​

Answer 1

Answer:

Given

$\alpha \: and \: \beta \: are \: the \: roots \: of \: the \: equation$

$p {x}^{2} - qx + c$

We know that Sum of roots

$\alpha + \beta = - b \div a$

Hence Sum of roots

= -(-q)/p

hence

$\alpha + \beta = q \div p$

Answer 2

Step-by-step explanation:

Correct Framed Question:-

If $\alpha$ and $\beta$ are the roots of Polynomial $px^2 - qx + c$ then find $\alpha$ and $\beta$

Required Answer:-

Concept:-

We know that:-

$\alpha$ + $\beta$ = $\dfrac{-b}{a}$

$\alpha$$\beta$ = $\dfrac{c}{a}$

So, these concepts will be applied.

Let's Do!

$\alpha$ + $\beta$ = $\dfrac{-b}{a}$

• Where a is p
• Where b is -q
• Where c is c

$\alpha$ + $\beta$ = $\dfrac{-(-q)}{p}$

$\alpha$ + $\beta$ = $\dfrac{q}{p}$

Is the required Answer.

Things to Note:-

$\alpha$$\beta$ = $\dfrac{c}{a}$

• Here also, the same a, b and c values are applied.
• Special Attention:-
• Minus sign turns plus if already there in Polynomial.