if a and b are the roots of quadratic equation x^2 +x -2 = 0 find the value of a^-1 - b^-1
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Answer:
p(x) = x^2 + x - 2
sum of zeroes = a+b = - ( coeff. of x) / (coeff. of x^2
= -1/1 = 1
product of zeroes = -2/1 = -2
1/a + 1/b = a+b/ab
on putting the required values, we get
-1/-2 = 1/2
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