Question

If a and b are the roots of the equation Px2 – Qx + R = 0, then what is the value of (1/a2) + (1/b2) + (a/b) + (b/a)?

A) Q2-2P2R+PPR2 B) Q2-2PRR+PPR2 C) Q2-2R2P+RP2R2 D) Q2-2PR2R+2PP2R2

Answer 1

Answer:

Q2-2p2r+ppr2 fiidhsggz

Answer 2

Answer:

let a=b=1

sum-2

product-1

equation x²-2x+1=0

P=1 ,Q=2,R=1

1/a²+1/b²+a/b+b/a=4 (put the value a&b)

Q²-2PR×R+P÷PR² this is satisfied put the value p q & r