If a and b are the roots of the equation x^2+2x+4=0
then the value of ((a^2÷b) + (b^2÷a))
is equal to
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0
Answer:
4
Step-by-step explanation:
(a^2÷b)+(b^2÷a)
(a*2÷b)+(b*2÷a)
(2a÷b)+(2b÷a)
2a÷b+2b÷a
2a÷a+2b÷b
2+2
=4.
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