Math, asked by gowtham9359, 1 year ago

if a and b are the roots of the equation x² - px+q=0 find the value of 1/a+1/b​


AdityaPrime: Answer Would Be p/q
gunit53: yes

Answers

Answered by gunit53
4

Answer:

p/q

Step-by-step explanation:

1/a+1/b=a+b/ab

a+b=p/1(-b/a)

ab=q/1(c/a)

ans=p/q

Answered by abhi569
8

Answer:

p / q.

Step-by-step explanation:

We know,

         quadratic equation in the form x^2 - Sx + P = 0 represents the sum and product of its roots as - S and P.

So, here, polynomial is x^2 - px + q = 0

      Sum of roots = - S = - p

                            = S = p

       Product of roots = q

⇒ 1 / a + 1 / b

⇒ ( a + b ) / ab

⇒ Sum of roots / product of roots

⇒ p / q

Hence the required value of 1 / a + 1 / b is p / q.

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