if a and b are the roots of the equation x² - px+q=0 find the value of 1/a+1/b
AdityaPrime:
Answer Would Be p/q
Answers
Answered by
4
Answer:
p/q
Step-by-step explanation:
1/a+1/b=a+b/ab
a+b=p/1(-b/a)
ab=q/1(c/a)
ans=p/q
Answered by
8
Answer:
p / q.
Step-by-step explanation:
We know,
quadratic equation in the form x^2 - Sx + P = 0 represents the sum and product of its roots as - S and P.
So, here, polynomial is x^2 - px + q = 0
Sum of roots = - S = - p
= S = p
Product of roots = q
⇒ 1 / a + 1 / b
⇒ ( a + b ) / ab
⇒ Sum of roots / product of roots
⇒ p / q
Hence the required value of 1 / a + 1 / b is p / q.
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