if a and b are the roots of the equation x2+x+1=0 then a2 +b2 is
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Answer:
-1
Step-by-step explanation:
Comparing the above eqn with αx^2+βx+c
α=1,β=1,c=1
Since a and b are the roots, we know sum of roots =(-β/α) and product of roots =(c/α)
So Here a+b= (-1/1)= -1
and ab = 1
Now a^2+b^2=(a+b)^2-2ab
= (-1)^2 - 2*1 = 1-2 =-1
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