Math, asked by ruparoy14318, 9 months ago

if a and b are the roots of the polynomial. x² - 5x + 6 then find the value of 1/a² + 1/b²​

Answers

Answered by AdityaPhadnis
1

Step-by-step explanation:

x²-5x+6

x²-2x-3x+6

x(x-2)-3(x-2)

(x-2)(x-3)

So, roots are 2,3

Let a=2 ,b=3

1/a² + 1/b² = 1/2² + 1/3²

= 1/4 + 1/9

= 13/36

Answered by amitsnh
1

Answer:

13/36

Step-by-step explanation:

given a and b are roots of the eqn

a+b = -(-5)/1 = 5

ab = 6/1 = 6

now

(1/a2+1/b2) = (a2+b2)/a2b2

= {(a+b)^2 - 2ab}/(ab)^2

= (5^2-2*6)/6^2

= (25-12)/36

= 13/36

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