Math, asked by prabhushree2014, 6 hours ago

if A and B are the roots of the quadratic equation 17x2 + 43x - 73 = 0, construct a quadratic equation whose roots are A + 2 and B + 2.
find me the answer​

Answers

Answered by xSoyaibImtiazAhmedx
1

Given quadratic equation:-

  • 17x² + 43x - 73 = 0

Roots:-

  • A and B

Now ,

Sum of roots = \frac{–43}{17}

→ A + B = \bold{\frac{–43}{17}} ——(i)

And Product of roots = \frac{–73}{17}

AB = \bold{\frac{–73}{17}} —— (ii)

To find:- Quadratic equation with roots (A+2) and (B+2) .

Sum of roots

= A + 2 + B + 2

= A + B + 4

= (-43/17) + 4 { from eqn (i) }

= 25/17

And Product of roots

= (A+2)(B+2)

= AB + 2A + 2B + 4

= (-73/17) + 2(A + B) + 4

= (-73/17) + 2 (-43/17) + 4

= -91/17

Quadratic equation with roots (A + B) and

(B + 2) ,

» - {(A + 2) + (B + 2)}x + (A+2)(B+2) = 0

- (25/17)x - (91/17) = 0

17x² - 25x - 91 = 0

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