Question

If a and b are the roots of the quadratic equation 5y2−7y+1=0 then find the value of (1/a+1/b)

Answer 1

hey...

★ ans= 7

★ for more details refer to the attachment

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Answer 2

Concept

The polynomial equations of degree 2 in one variable is called as quadratic equations.

Given

5y² - 7y + 1 = 0

Find

1/a + 1/b

Solution

a and b are the roots of the equation 5y² - 7y + 1 = 0.

We know that

Sum of roots = - b' / a'  

Product of roots = c' / a'

where b'  = -7 and a' = 5 and c' = 1  

So

a + b = 7/5

a * b = 1/5

We need to calculate

1/a +1/b

1/a +1/b = ( b+a )/a*b

1/a +1/b = (7/5) / (1/5)

1/a +1/b = 7

The value of 1/a +1/b for the quadratic equation 5y²−7y+1=0 is 7.

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