Math, asked by Alanpeace, 1 year ago

if a and b are the roots of the quadratic equation x^2+√2x+3=0,from the quadratic polynomial with zeros 1/a,1/b​

Answers

Answered by ayadav1111
1

Answer:

a  +  b =  -  \sqrt{2}

a b = 3

when \: root \: are \:  \frac{1}{a}  \: and \frac{1}{b \: } then \: polynomial \:

p(x) =  {x}^{2}  + ( \frac{1}{a}  +  \frac{1}{b} )x +  \frac{1}{a}  \times  \frac{1}{b}

 =  {x}^{2}  +  \frac{a + b}{ab} x +  \frac{1}{ab}

 =  {x}^{2}   -   \frac{ \sqrt{2} }{3} x +  \frac{1}{3}

 \frac{1}{3} (3 {x}^{2}  -  \sqrt{2} x + 1)

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