If a and b are the roots of the quadratic equation x^2 - 5x + 3(k-1) = 0 are such that a-b =11. Find 'k'
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If α and β are the roots of Quadratic Equation px² + qx + r = 0 then :
Sum of the roots : α + β = -q/p
Product of the roots : α × β = r/p
Given Quadratic Equation is x² - 5x + 3(k - 1) = 0 and its roots are 'a' and 'b'
By comparing with the above, we can say that p = 1 and q = -5 and r = 3(k - 1) and α = a and β = b
⇒ Sum of the roots : a + b = 5
⇒ Product of the roots : a × b = 3(k - 1)
it is also given that a - b = 11
Adding a + b = 5 and a - b = 11 we get :
⇒ 2a = 16
⇒ a = 8 and b = -3
Product of the roots : a × b = 3(k - 1)
⇒ 8 × -3 = 3k - 3
⇒ -24 = 3k - 3
⇒ 3k = -21
⇒ k = -7
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