if A and B are the roots of the quadratic polynomial f(x) = x²-2x+3x, then find the polynomial was roots are (a-1/a+1), (B-1/B+1)
Answers
2.051 kilometre from 250 subtract 20.75 we get
\textrm{Rs} 2.50Rs2.50
(b) Subtracting 202.54 m from 250 m we get
47.46\textrm {m}47.46m
(c) Subtracting Rs 5.36 from Rs 8.40 we get
\textrm{Rs} 3.04Rs3.04
(d) Subtracting 2.051 km from 5.206 km we get 3.155\textrm{km}3.155km
(e) Subtracting 0.314kg from 2.107 kg we get
1.793 \textrm{kg}1.793kg
Step-by-step explanation:
(a) Subtracting Rs 18.25 from Rs 20.75 we get
\textrm{Rs} 20.75- \textrm{Rs} 18.25= \textrm{Rs} 2.50Rs20.75−Rs18.25=Rs2.50
(b) Subtracting 202.54 m from 250 m we get
250 \textrm{m}-202.54\textrm{m}=47.46\textrm {m}250m−202.54m=47.46m
(c) Subtracting Rs 5.36 from Rs 8.40 we get
\textrm{Rs} 8.40-\textrm{Rs} 5.36=\textrm{Rs} 3.04Rs8.40−Rs5.36=Rs3.04
(d) Subtracting 2.051 km from 5.206 km we get
5.206 \textrm{km} - 2.051\textrm{km}= 3.155\textrm{km}5.206km−2.051km=3.155km
(e) Subtracting 0.314kg from 2.107 kg we get
2.107 \textrm{kg}-0.314 \textrm{kg}2.107kg−0.314kg =1.793 \textrm{kg}=1.793kg
Answer:
Given that
a and b are the zeros of
x
2
−2x+3
Then,
We know that
Sum of zeros =−
coefficient. of x
2
coefficient. of x
a+b=−
+1
−2
a+b=2−−−−−−−−(1)
Now,
Product of zeros =
coefficient. of x
2
constant term
a.b=
1
3
ab=3−−−−−−−−−−−(2)
If 2a+3 and 2b+3 are the zeros of other polynomial.
Then
Sum of zeros =2a+3+2b+3
=2(a+b)+6
=2(2)+6
=10
Sum of zeros =10
Product of zeros =(2a+3)(2b+3)
=4ab+6a+6b+9
=4ab+6(a+b)+9
=4×3+6×2+9
=12+12+9
=24+9
Product of zeros =33
Now,
Equation of polynomial
x
2
− (Sum of zeros) x+ product of zeros =0
x
2
−10x+33=0
Hence, this is the answer.
Step-by-step explanation:
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