Math, asked by meghaagrawal234, 9 months ago

if a and b are the roots of x^2=x+1 then values of a^2/b-b^2/a is




Answers

Answered by AlluringNightingale
11

Answér :

a²/b - b²/a = -2√5

Solution :

Please refer to the attachments .

Note :

★ The possible values of the variable which satisfy the equation are called its roots or solutions .

★ A quadratic equation can have atmost two roots .

★ The general form of a quadratic equation is given as ; Ax² + Bx + C = 0

★ If a and b are the roots of the quadratic equation Ax² + Bx + C = 0 , then ;

• Sum of roots , (a + b) = -B/A

• Product of roots , (ab) = C/A

★ If a and ßlb are the roots of a quadratic equation , then that quadratic equation is given as : k•[ x² - (a + b)x + ab ] = 0 , k ≠ 0.

★ The discriminant , D of the quadratic equation Ax² + Bx + C = 0 is given by ;

D = B² - 4AC

★ If D = 0 , then the roots are real and equal .

★ If D > 0 , then the roots are real and distinct .

★ If D < 0 , then the roots are unreal (imaginary) .

Attachments:
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