Question

If a and b are the roots of
x² - kx + 16 = 0
a2+b²=32
then find the value of k​

Answer 1

Answer:

(c) -8, 8 a + b = k ….(1) ab = 16 ….(2) a2 + b2 = (a + b)2 – 2ab = 32. k2 – 32 = 32 ⇒ k2 = 64 ⇒ k = ±8Read more on Sarthaks.com - https://www.sarthaks.com/909053/if-a-and-b-are-the-roots-of-the-equation-x-2-kx-16-0-and-satisfy-a-2-b-2-32-then-the-value-of-k-is-a-10

Answer 2

Answer:

Step-by-step explanation:

a + b = k ….(1)  ab = 16 ….(2) a2 + b2 = (a + b)2 – 2ab = 32. k2 – 32 = 32 ⇒ k2 = 64 ⇒ k = ±8

ANSWERED BY GAUTHMATH