if a and b are the roots of x2+x+1=0 then a3+b3 is equal to
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The value of α³ + β³ = 2.
Step-by-step explanation:
★ Given that :
- α and β are the zeroes of the Quadratic Polynomial p(x) = x² + x + 1 = 0
★ To find :
- Value of α³ + β³ .
★ Let :
◼ The general form of the Quadratic Polynomial is : ax² + bx + c = 0.
◼ Consider the given Quadratic Polynomial.
- a = 1
- b = 1
- c = 1
➡ Sum of the zeroes : α + β = -b/a = -1/1 = 1
➡ Product of the zeroes : αβ = c/a = 1/1 = 1
Now, we know the identity :
☯ (a + b)³ = a³ + b³ + 3ab(a + b)
Consider it as
☯ (α + β)³ = α³ + β³ + 3αβ(α + β)
- Substitute the zeroes.
➠ (- 1)³ = α³ + β³ + 3(1)(-1)
➠ - 1 = α³ + β³ - 3
➠ - 1 + 3 = α³ + β³
➠ α³ + β³ = 2.
∴ The value of α³ + β³ = 2
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