Question

if a and B are the two roots of the equation x2 + 3x + 4 = 0 then form
the equation whose two roots are (a - b)2 and (a + B)2?.
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Answer 1

Step-by-step explanation:

given x^2+3x+4 that a nad b are the roots of the equation

let a = 1,b=3, c=4

b^2-4ac

9-16=-7

we know that b^2-4ac <0 then root are imaginary

then roots will be

p+iq, p-iq

-3+7i/2, -3-7i/2 (i=iota) i=√-1, i^2= -1

a =-3+i7/2

b=-3-17/2

(I) (a-b) ^2

[-3+7i/2 -(-3-7i) /2]^2

(14i/2)^2

(7i)^2

49i^2

-49

2) (a+b) ^2

[-3+7i/2+(-3-7i/2)]^2

(-3)^2

9