Question

if a and B are the two zeros of polynomial 6y2-7y+2, find te quadratic polynomial whose zeros are 1/a and 1/B

Answer 1

Heya here .....

Solution Given below ↓↓↓
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By using the relationship between the zeros of the Polynomial .

we have -
$sum \: of \: \: zeros = \frac{ - ( - coefficient \: of \: x)}{coefficient \: of \: {x}^{2} }$

$product \: of \: zeros = \frac{constant \: \: term}{coefficient \: of \: {x}^{2} }$
$\alpha + \beta = \frac{ - ( - 7)}{6} \: \: and \: \\ \\ \alpha \beta = \frac{2}{6}$
$\alpha + \beta = \frac{7}{6} \: \: and \: \alpha \beta = \frac{2}{6}$
Now ,

$\frac{1}{ \alpha } + \frac{1}{ \beta } = \frac{ \alpha + \beta }{ \alpha \beta } \\ \\ = > \frac{ \frac{7}{6} }{ \frac{2}{6} }$
=> 3.5 Answer .

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Hope it's helps you.
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