If a and B are the xeros of quadratic polynomin f(T)=t2-4t+3 fine the value of a4ß3+a3ß4
Answers
Answered by
1
Answer:
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Step-by-step explanation:
a4ß
Answered by
0
Answer:
α⁴β³ + α³β⁴ =108
Step-by-step explanation:
f(t)=t²-4t+3
α,β are zeros of f(t)
So α+β =-(-4)/1=4
αβ =3/1=3
Thus
α⁴β³ + α³β⁴
=α³β³( α+β )
=(αβ )³(4)
=(3)³*4
=27*4
α⁴β³ + α³β⁴ =108
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