If a and b are the zero of quadratic polynomial f(x)= 3x2-5x-2 then evaluate (a3+b3)
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Answered by
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it is given that 3x^2-5x-2 is a zero polynomial
therefore by splitting the middle term we get ,
⇒3x^2+x-6x-2
⇒let we factorize this term as ,
x(3x+1)-2(3x+1)
⇒(x-2 ) and (3x+1) are the factors of this polynomial
∴as they have given zero of the polynomial we get
x-2=0
⇒x=2-----------------let we taken it as a
3x+1=0
⇒x=-1/3--------------------let we taken as b
now let we find a^3+b^3
as we know that a^3+b^3=(a+b)(a^2-ab+b^2)
∴(2-1/3)(4-2/3+1/9)
(5/3)(31/9)
⇒155/27
therefore by splitting the middle term we get ,
⇒3x^2+x-6x-2
⇒let we factorize this term as ,
x(3x+1)-2(3x+1)
⇒(x-2 ) and (3x+1) are the factors of this polynomial
∴as they have given zero of the polynomial we get
x-2=0
⇒x=2-----------------let we taken it as a
3x+1=0
⇒x=-1/3--------------------let we taken as b
now let we find a^3+b^3
as we know that a^3+b^3=(a+b)(a^2-ab+b^2)
∴(2-1/3)(4-2/3+1/9)
(5/3)(31/9)
⇒155/27
anuritha:
my friend thanks for giving this chance to answer this to make my concepts even more clear .
a small advance like a friend is that please that as square or cubes likes x^2,x^3 where ^ symbol is used to denotes that.
if you like this please rate as we can rectify the mistakes if you think it is the branliest answer please rate
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2
Answer:
the write answer is 3×3×4hshv nwaa jaaajasswaa ss hjwgwk ws
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