Question

If a and B are the zeroes of 4y² + 3y + 7, then find the value of a ¹¹+ B¹​

Answer 1

Answer:

This will be very complicated unless you take -3y or -7. Let us take -7

4y^2 +3y-7

Factorise by mid term splitting

=(4y+7)(y-1)

So zeroes are -7/4 and 1

Let us take a=1 and B=-7/4

a^11+B^1=(1)^11+(-7/4)=1-(7/4)= -3/4 Ans