Question

If a and b are the zeroes of 8x2 - 2x – 3 = 0, then find the value of 1/a + 1/b.

Answer 1

Answer:

$\frac{ - 5}{4}$

Step-by-step explanation:

$8 {x}^{2} - 2x - 3 = 0 \\ 8 {x}^{2} + 4x - 6x - 3 = 0 \\ \\ 4x(2x + 1) - 3(2x + 1) \\ \\ (4x - 3)(2x + 1) = 0 \\ \\ x = \frac{3}{4} and \: x = \frac{ - 1}{2}$

$a = \frac{3}{4} \\ b = \frac{ - 1}{2} \\ \frac{1}{a} + \frac{1}{b} \\ \\ \frac{3}{4} + \frac{ - 2}{1} \\ \\ \frac{3}{4} - \frac{8}{4} \\ \\ \frac{ - 5}{4}$

Answer 2

Step-by-step explanation:

1. step 1
2. step 1 8×2-2×(-3) = 0
3. step 1 8×2-2×(-3) = 0step 2
4. step 1 8×2-2×(-3) = 0step 216- (-6) = 0
5. step 1 8×2-2×(-3) = 0step 216- (-6) = 0step 3
6. step 1 8×2-2×(-3) = 0step 216- (-6) = 0step 32=0
7. step 1 8×2-2×(-3) = 0step 216- (-6) = 0step 32=0step 4
8. step 1 8×2-2×(-3) = 0step 216- (-6) = 0step 32=0step 4then, we the value of :
9. step 1 8×2-2×(-3) = 0step 216- (-6) = 0step 32=0step 4then, we the value of : 1/a +1/b
10. step 1 8×2-2×(-3) = 0step 216- (-6) = 0step 32=0step 4then, we the value of : 1/a +1/b2ab