Question

if a and b are the zeroes of a polynomial such that a+b=-6 and ab=5 then find the polynomial.​

Answer 1

Answer:

$the \: polynomial \: is \\ {x}^{2} - (a + b)x + ab \: \\ {x}^{2} - ( - 6)x + 5 \\ {x }^{2} + 6x + 5$

And equation is :

${x}^{2} + 6x + 5 = 0$

Answer 2

Answer:

α + β= 6 = sum of zeros and

αβ = 4 = Product of zeroes

We know that, if α and β are the zeros of the polynomial then the quadratic polynomial can be x2 – (α + β) x + αβ

Now substituting the values, we get

x2 – 6x + 4, which is required polynomial.

Step-by-step explanation:

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