if a and b are the zeroes of a quadratic polynomial f (x) =x2 -2
x + 3 then find a quadratic polynomial whose zeroes a-1/a+1 and b-1 / b+1
Answers
Answer:
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Answer:
0 and -6
Step-by-step explanation:
Let the quadratic polynomial be:
p(x) = x² + (a + 1)x + b
The two zeros are 2 and -3.
So p(2) = 0
∴2² + (a+1)*2 + b = 0
∴4 + 2a + 2 + b = 0
∴2a + b = -6 -------------------- (1)
Also, p(-3) = 0
∴(-3)² + (a+1) * (-3) + b = 0
∴9 -3a - 3 + b = 0
∴6 = 3a - b
∴3a - b = 6 ----------------- (2)
Solving the two equations by Elimination Method (You can use other methods also),
2a + b = -6
3a - b = 6 (Adding (1) and (2) )
----------------
∴ 5a = 0
∴ a = 0
Substituting a = 0 in equation (1),
2a + b = -6
∴2(0) + b = -6
∴0 + b = -6
∴b = -6
Thus a = 0 and b = -6.