Math, asked by Joyshree123, 1 year ago

if a and b are the zeroes of a quadratic polynomial f(x) = x²-4x+3 find the value of a⁴b²+a²b⁴​

Answers

Answered by snehadubey529
29

x^2 - 4x + 3

x^2 - 3x -x + 3

x(x-3)-1(x-3)

(x-3)(x-1)

a=3 , b= 1

Put the value in a^4b^2+a^2b^4

(3)^4(1)^2 + (3)^2(1)^4

243 X 1 + 9 X 1

243+9

252

Hope it helps.

Answered by shilshaurya5606
13

Answer:

90

Step-by-step explanation:

x² - 4x + 3 = 0

=> x² - x - 3x + 3 = 0

=> x(x - 1) - 3(x - 1) = 0

=> (x - 1)(x - 3) = 0

∴ x = 1, 3

Now, let a = 1 and b = 3 (vice-versa will give the same answer)

=> 1⁴(3)² + 1²(3)⁴

=> 1(9) + 1(81) => 9 + 81 => 90

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