if a and b are the zeroes of a quadratic polynomial f(x) = x²-4x+3 find the value of a⁴b²+a²b⁴
Answers
Answered by
29
x^2 - 4x + 3
x^2 - 3x -x + 3
x(x-3)-1(x-3)
(x-3)(x-1)
a=3 , b= 1
Put the value in a^4b^2+a^2b^4
(3)^4(1)^2 + (3)^2(1)^4
243 X 1 + 9 X 1
243+9
252
Hope it helps.
Answered by
13
Answer:
90
Step-by-step explanation:
x² - 4x + 3 = 0
=> x² - x - 3x + 3 = 0
=> x(x - 1) - 3(x - 1) = 0
=> (x - 1)(x - 3) = 0
∴ x = 1, 3
Now, let a = 1 and b = 3 (vice-versa will give the same answer)
=> 1⁴(3)² + 1²(3)⁴
=> 1(9) + 1(81) => 9 + 81 => 90
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