IF A AND B ARE THE ZEROES OF POLYNIMOALS X2+7X+7FIND THE NEW POLYNOMIAL WHOSE ZEROES ARE 1/A AND 1/B
Answers
Answered by
2
Step-by-step explanation:
Answer:
\text{The value of }\frac{1}{\alpha}+\frac{1}{\beta}-2\alpha \beta \text{ is }-15
Step-by-step explanation:
Given that α and β are the zeroes of the polynomial
x^2+7x+7
we have to find the value of
\frac{1}{\alpha}+\frac{1}{\beta}-2\alpha \beta
The polynomial is x^2+7x+7
By comparing with standard form ax^2+bx+c=0
⇒ a=1, b=7 and c=7
\text{Sum of zeroes= }\alpha+\beta=\frac{-b}{a}=-\frac{-7}{1}=-7
\text{Product of zeroes= }\alpha.\beta=\frac{c}{a}=\frac{7}{1}=7
Now,
\frac{1}{\alpha}+\frac{1}{\beta}-2\alpha \beta
=\frac{\beta+\alpha}{\alpha \beta}-2\alpha \beta
=\frac{-7}{7}-2(7)=-1-14=-15
Answered by
1
Answer:
so, I am not giving process
I am only tell answer is -15
so, mark me brainest
Similar questions