Math, asked by mirzaadeebrazabaig, 10 months ago

IF A AND B ARE THE ZEROES OF POLYNIMOALS X2+7X+7FIND THE NEW POLYNOMIAL WHOSE ZEROES ARE 1/A AND 1/B

Answers

Answered by rishi102684
2

Step-by-step explanation:

Answer:

\text{The value of }\frac{1}{\alpha}+\frac{1}{\beta}-2\alpha \beta \text{ is }-15

Step-by-step explanation:

Given that α and β are the zeroes of the polynomial

x^2+7x+7

we have to find the value of

\frac{1}{\alpha}+\frac{1}{\beta}-2\alpha \beta

The polynomial is x^2+7x+7

By comparing with standard form ax^2+bx+c=0

⇒ a=1, b=7 and c=7

\text{Sum of zeroes= }\alpha+\beta=\frac{-b}{a}=-\frac{-7}{1}=-7

\text{Product of zeroes= }\alpha.\beta=\frac{c}{a}=\frac{7}{1}=7

Now,

\frac{1}{\alpha}+\frac{1}{\beta}-2\alpha \beta

=\frac{\beta+\alpha}{\alpha \beta}-2\alpha \beta

=\frac{-7}{7}-2(7)=-1-14=-15

Answered by jayagokina
1

Answer:

so, I am not giving process

I am only tell answer is -15

so, mark me brainest

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