if a and b are the zeroes of quadratic polynomial p(x):x'2+x-2 find the value of1/a-1/b
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x'2+x-2=0
x'2+2x-x-2=0
x(x+2)-1(x+2)=0
x=1&x=-2
So a=1 & b=-2
Now to find:1/a-1/b
=1/1-1/(-2)
=1+1/2
=3/2
x'2+2x-x-2=0
x(x+2)-1(x+2)=0
x=1&x=-2
So a=1 & b=-2
Now to find:1/a-1/b
=1/1-1/(-2)
=1+1/2
=3/2
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