If a and b are the zeroes of the lolynomial 6x^2+x-2 find the value of (a/b+b/a)
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6x^2-3x+4x-2
=3x(2x-1) + 2(2x-1)
=>zeroes are : -2/3, 1/2
-1/6=a+b
-1/3=ab
Now,
a/b+b/a
=a^2 + b^2/ab
=√(a+b)^2-2ab/ab
=√1/36+2/3 /ab
=5/6 /ab
=5/6 * -3/1
=-5/2
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