Question

If a and B are the zeroes of the polinomial 2-3x-x^2

Answer 1

Correct Question

Find the zeros of polynomial

x² - 3x + 2

Solution

→ x² - 3x + 2 = 0

★ Solve this by splitting middle term

→ x² - 2x - x + 2 = 0

→ x(x - 2) - 1(x - 2) = 0

→ (x - 2)(x - 1) = 0

Either

→ (x - 2) = 0

→ x = 2

Or

→ (x - 1) = 0

→ x = 1

Hence, 2 and 1 are the zeros of given polynomial

Answer 2

✯✯ QUESTION ✯✯

If a and B are the zeroes of the polynomial 2-3x-x²..

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✰✰ ANSWER ✰✰

$\longmapsto\tt{{x}^{2}-3x+2}$

By Splitting Middle Term : -

$\longmapsto\tt{{x}^{2}(2x+1x)+2=0}$

$\longmapsto\tt{{x}^{2}-2x-1x+2=0}$

$\longmapsto\tt{x(x-2)-1(x-2)}$

$\longmapsto\tt{(x-1)(x-2)}$

• x = 1
• x = 1

➮So , 1 and 2 are the zeroes of polynomial x²-3x+2..

➥Here : -

• a = 1
• b = -3
• c = 2

★Sum of Zeroes : -

$\longmapsto\tt{\alpha+\beta=\dfrac{-b}{a}}$

$\longmapsto\tt{1+2=\dfrac{-(-3)}{1}}$

$\longmapsto\tt\bold{3=3}$

$\red\longmapsto\:\large\underline{\boxed{\bf\green{L.H.S}\orange{=}\purple{R.H.S}}}$

★Product Of Zeroes : -

$\longmapsto\tt\bold{\alpha\beta=\dfrac{c}{a}}$

$\longmapsto\tt{1\times{2}=\dfrac{2}{1}}$

$\longmapsto\tt\bold{2=2}$

$\green\longmapsto\:\large\underline{\boxed{\bf\pink{L.H.S}\orange{=}\orange{R.H.S}}}$

✺ HENCE VERIFIED ✺